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Showing posts with the label FEM

Beam problems (part1- simply supported beam with UDL and point load)

  Beam problem Problem1 Description: A simply supported Beam of 4000 mm length as shown in fig. A point load of 500 N and UDL load of 0.4 N/mm will be applied to a solid steel beam with a rectangular cross section. The cross section of the beam is 200mm*300mm while the modulus of elasticity of the steel is 200GPa and Poisson’s ratio is 0.3. Find the maximum deflection, Shear forces, Bending moment, and Reaction forces. problem figure Results: Discipline: Structural Analysis Type: Static Element type: Beam, 2 node 188 Material model: Linear elastic isotropic. Section: common section of beam – rectangular c/s, B= 200, H=300. Key points: 4 key points are taken at x= 0, 2000, 3000, 4000. (*all dimensions are in mm) Meshing: for all 3 elements, the number of element divisions are taken as 30.  Displacement: at key-point1 (x=0), due to hinged support constraints are chosen in translation in all directions and rotation in x and y direction. Because the beam can only rotate in...

2-D Static Stress Analysis on a Flat plate with Hole (part2)

  2-D Static Stress Analysis on a Flat plate with Hole Problem2 Description: Examine the stress concentrations in a flat rectangular plate of size 0.5 × 0.2 with three holes whose dimensions are as follows, Centre X Y Radius Hole 1 0.25 0.1 0.01 Hole 2 0.23 0.1 0.005 Hole 3 0.27 0.1 0.005 Given: Young’s Modulus = 70e9, Poisson ratio = 0.3, Pressure 100 N, Thickness of plate is 0.3. * All dimensions are in meters. For,   Results: Discipline: Structural Analysis Type: Static Element type: Solid, Quadrilateral 8 node 183 Material model: Linear elastic isotropic Material option: Plane stress with thickness Real constant: 0.3m thickness (because given problem is 3D plate problem) Max deflection:   In given 3D plate case, applied pressure load at free end of plate = -100/0.3 (= force/width)                            ...

2-D Static Stress Analysis on a Flat plate with Hole (part1)

2-D Static Stress Analysis on a Flat plate with Hole Problem1 Description: Examine the stress concentrations in a flat rectangular plate of size 0.5 × 0.2 with three holes whose dimensions are as follows, Centre X Y Radius Hole 1 0.25 0.1 0.01 Hole 2 0.23 0.1 0.005 Hole 3 0.27 0.1 0.005 Given: Young’s Modulus = 70e9, Poisson ratio = 0.3, Pressure 100 N: * All dimensions are in meters. For,   Results: Discipline: Structural Analysis Type: Static Element type: Solid, Quadrilateral 4 node 182 Material model: Linear elastic isotropic   Max deflection:   After applying 100N tensile force at the free end, the plate gets a maximum deformation of 0.72E-9 m in X-direction. Element solution:   For an elemental solution, using the 1st principal stress approach we get max stress 290.34  N/m2. Maximum stress occurs at element no. 1270.   Vector plot:   Using a vector plot to visualize translations U, we get maximum translation at node 3, which is 0.72E-9 m in ...

3D Dimensional Truss analysis using ANSYS APDL

3D Dimensional Truss Problem Description: Determine the nodal deflections, reaction forces, and stress for the truss system shown below (E = 200GPa, Pipe diameter = 30 mm, Wall thickness =2mm   Results: Discipline: Structural Analysis Type: Static No of elements: 06 No of Nodes:   05 Max Deflection (Image & Table)      PRINT REACTION SOLUTIONS PER NODE     ***** POST1 TOTAL REACTION SOLUTION LISTING *****                           LOAD STEP= 1  SUBSTEP= 1                                            TIME= 1.0000      LOAD CASE=   0                                         THE FOLLOWING X,Y,Z SOLUTIONS ARE IN THE GLOBA...

2D Dimensional Truss analysis using ANSYS APDL

2D Dimensional Truss Problem Description: Determine the nodal deflections, reaction forces, and stress for the truss system shown below (E = 200GPa, A = 3250mm2). Results: Discipline: Structural Analysis Type: Static No of elements: 11 No of Nodes: 07   Max Deflection (Image & Table)      PRINT U NODAL SOLUTION PER NODE   ***** POST1 NODAL DEGREE OF FREEDOM LISTING *****                          LOAD STEP= 1 SUBSTEP= 1                                            TIME= 1.0000  LOAD CASE= 0         THE FOLLOWING DEGREE OF FREEDOM RESULTS ARE IN THE GLOBAL COORDINATE SYSTEM                          ...